Taxi Fare
Programming Basics · C++
TASK
Problem
In “Taxi Fare”, given base fare and number of kilometers, print base + 15*km.
EXAMPLE
Example
100 4
160
LIMITS
Constraints
All values are non-negative and at most 10^12; every capacity/divisor is positive.
LEARN
Theory for this problem
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Translate the story into a small arithmetic formula. Use ceiling division `(a+b-1)/b` when a partially filled unit still counts.
Connection to “Taxi Fare”: here, intermediate values are best kept in named variables so the formula stays readable and data types remain clear.
NEED HELP?
Hints
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['Identify what each input value means before writing the formula.', 'After solving “Taxi Fare”, verify the algorithm on your own small example and on an allowed boundary case. Print only the required result with no extra text.']
ANSWER
Solution
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#include <iostream>
using namespace std;
int main() {
long long base, km;
cin >> base >> km;
cout << base + 15 * km << '\n';
return 0;
}