TASK

Problem

#33

Given an integer `n`, print `positive` if `n > 0`, `negative` if `n < 0`, and `zero` otherwise.

EXAMPLE

Example

Input

-5

Output

negative

LIMITS

Constraints

All integer magnitudes are at most 10^9; divisors are non-zero where used.

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LEARN Theory for this problem

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`if`, comparison operators, and logical operators let a program choose output according to a condition.

Connection to “Sign of Number”: here, branching selects a case using a Boolean condition; test order matters when cases overlap.

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NEED HELP? Hints

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['Write the condition directly and print exactly the required value.', 'After solving “Sign of Number”, verify the algorithm on your own small example and on an allowed boundary case. Print only the required result with no extra text.']

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ANSWER Solution

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#include <iostream>
#include <algorithm>
#include <cstdlib>
using namespace std;
int main() {
    long long n;
    cin >> n;
    if (n > 0) cout << "positive" << '\n';
    else if (n < 0) cout << "negative" << '\n';
    else cout << "zero" << '\n';
    return 0;
}