Even or Odd
Programming Basics · C++
TASK
Problem
Given an integer `n`, print `even` if it is divisible by 2; otherwise print `odd`.
EXAMPLE
Example
-5
odd
LIMITS
Constraints
All integer magnitudes are at most 10^9; divisors are non-zero where used.
LEARN
Theory for this problem
+
`if`, comparison operators, and logical operators let a program choose output according to a condition.
Connection to “Even or Odd”: here, intermediate values are best kept in named variables so the formula stays readable and data types remain clear.
NEED HELP?
Hints
+
['Write the condition directly and print exactly the required value.', 'After solving “Even or Odd”, verify the algorithm on your own small example and on an allowed boundary case. Print only the required result with no extra text.']
ANSWER
Solution
+
#include <iostream>
#include <algorithm>
#include <cstdlib>
using namespace std;
int main() {
long long n;
cin >> n;
cout << (n % 2 == 0 ? "even" : "odd") << '\n';
return 0;
}